{"@context":"https://schema.org","@type":"NewsArticle","generatedAt":"2026-07-23T08:01:28.298Z","headline":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","description":"Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","url":"https://www.aioga.com/news/cmrlpa4rs00eybih5qt1ohw0o/","mainEntityOfPage":"https://www.aioga.com/news/cmrlpa4rs00eybih5qt1ohw0o/","datePublished":"2026-07-15T06:15:13.589Z","dateModified":"2026-07-15T06:15:13.589Z","inLanguage":"zh-CN","publisher":{"@type":"NewsMediaOrganization","name":"Aioga","url":"https://www.aioga.com"},"citation":["https://www.starfleetmath.com/","https://aihot.virxact.com/items/cmrlpa4rs00eybih5qt1ohw0o"],"canonicalUrl":"https://www.aioga.com/news/cmrlpa4rs00eybih5qt1ohw0o/","directAnswer":{"@type":"Answer","text":"Aioga 编辑摘要：Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。 Aioga 将其归入「产品更新」方向，重点关注它对真实使用和行业竞争的影响。","url":"https://www.aioga.com/news/cmrlpa4rs00eybih5qt1ohw0o/","dateCreated":"2026-07-15T06:15:13.589Z","author":{"@type":"Organization","@id":"https://www.aioga.com/authors/aioga-editorial/#editorial-team","name":"Aioga Editorial Team","url":"https://www.aioga.com/authors/aioga-editorial/"}},"evidence":[{"@type":"CreativeWork","name":"starfleetmath.com source article","url":"https://www.starfleetmath.com/","datePublished":"2026-07-15T06:15:13.589Z","provider":{"@type":"Organization","name":"starfleetmath.com","url":"https://www.starfleetmath.com/"}},{"@type":"CreativeWork","name":"AIHot archive record","url":"https://aihot.virxact.com/items/cmrlpa4rs00eybih5qt1ohw0o","datePublished":"2026-07-15T06:15:13.589Z","provider":{"@type":"Organization","name":"AIHot","url":"https://aihot.virxact.com/items/cmrlpa4rs00eybih5qt1ohw0o"}}],"aggregationSource":"Hacker News 热门（buzzing.cc 中文翻译）","originalPublisher":{"name":"starfleetmath.com","url":"https://www.starfleetmath.com/"},"article":{"id":"cmrlpa4rs00eybih5qt1ohw0o","slug":"cmrlpa4rs00eybih5qt1ohw0o","url":"https://www.aioga.com/news/cmrlpa4rs00eybih5qt1ohw0o/","title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","title_en":"利用20个并行运行的Codex账户解决20个埃尔德什问题","summary":"Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","source":"Hacker News 热门（buzzing.cc 中文翻译）","sourceUrl":"https://www.starfleetmath.com/","aiHotUrl":"https://aihot.virxact.com/items/cmrlpa4rs00eybih5qt1ohw0o","publishedAt":"2026-07-15T06:15:13.589Z","category":"产品更新","score":36,"selected":false,"articleBody":["Built by Colin Snyder · colin@colinsnyder.com：mailto:colin@colinsnyder.com","Advised by Mike Kim · proposed solutions ↓：#solutions","Inspired by Ignis · previously built by Myself, Dhruv Agarwal, & Nitin Kesarwani at the New Turing Institute","These are “proposed solutions”, so if you take issue with any of them, please let us know.","Star Fleet is an AI system that solves the world's hardest open mathematics problems using Lean 4. It's a Mac desktop app that controls up to 20 custom agentic harnesses called “starships” in parallel, each running its own GPT-5.6 instance on a dedicated 60-vCPU server and working on a separate math problem. Everything is built from scratch in TypeScript & Bun.","Many problems listed as “open” carry informal or partial answers already available online; we tried extremely hard to avoid working on any such problems (but most likely failed in certain cases). If there are attribution mistakes, please let us know.","Let a , b , c ≥ 1 a,b,c\\geq 1 a , b , c ≥ 1 be three integers which are pairwise coprime. Is every large integer the sum of distinct integers of the form a k b l c m a^kb^lc^m a k b l c m ( k , l , m ≥ 0 k,l,m\\geq 0 k , l , m ≥ 0 ), none of which divide any other?","(Erdős Problem #123 — prize: $250 — number theory — https://www.erdosproblems.com/123)","For every pairwise-coprime triple of integers a,b,c>1, every sufficiently large integer is a sum of distinct terms a^i b^j c^k such that no selected term divides another. In Lean, this is the theorem Erdos123.erdos_123 : Erdos123.IntendedStatement.","For pairwise-coprime integers a , b , c > 1 a,b,c>1 a , b , c > 1 , consider the numbers","The question asks whether every sufficiently large integer is a sum of distinct such numbers, with the additional requirement that no chosen summand divides another .","The divisibility condition is the real source of difficulty. Ordinary completeness arguments can use many terms from different scales, but terms from different scales tend to be comparable by divisibility. Conversely, a set chosen to be a divisibility antichain can be too arithmetically sparse to fill consecutive integers.","Earlier work had developed a powerful reduction scheme: choose a correction with the required residue modulo one base, subtract it, divide by that base, and induct. For particular triples this succeeds after a finite computer check. In general, however, it leaves a stubborn finite-seed problem : one must first represent every integer in a multiplicatively wide interval [ N , C N ] [N,CN] [ N , C N ] . The correction induction does not construct that interval; it only propagates it.","This explains why several attractive partial ideas did not finish the problem:","The important lesson was that large additive width is not enough . The lower endpoint has to remain under quantitative control.","The first structural simplification is to work on one homogeneous exponent level","For pairwise-coprime bases greater than one, divisibility of monomials is coordinatewise comparison of their exponents. Therefore two distinct monomials on the same level can never divide one another. Every subset of a homogeneous level is automatically primitive.","This turns the problem into an additive question about subset sums while making primitiveness essentially free—as long as all pieces of the construction can be placed on the same exact degree.","An edge-code construction supplies c n c^n c n primitive subset sums on one level with distinct residues modulo c n c^n c n and a bounded carry. Coloring by that carry and applying finite van der Waerden, itself obtained from Mathlib’s Hales–Jewett theorem, gives arbitrarily long exact arithmetic progressions of primitive homogeneous subset sums.","and then choose v > 0 v>0 v > 0 so that","Define two coprime homogeneous translation weights","Copies of one AP digit family are translated by the weights","The choice u > H + 1 u>H+1 u > H + 1 places different copies in disjoint bands of the b b b -exponent. Multiplying every term by a b c abc ab c makes every AP term strict-interior. All copies then lie on one exact exponent degree.","A bounded homogeneous-radix lemma proves that coefficient sums","contain a full interval of width at least 2 A B M + 1 2AB^{M+1} 2 A B M + 1 . Replacing each coefficient by the corresponding AP digit set realizes this as an interval on a lattice of step a b c d abc\\,d ab c d , where d d d is the AP difference.","The next ingredient constructs, on every sufficiently high exact degree , a primitive correction for each residue modulo any prescribed modulus. The corrections are supported on the three coordinate faces and, in the ordered case, have total size bounded by","Apply this with modulus a b c d abc\\,d ab c d , on the same exact degree as the AP-radix construction. Face-supported corrections are disjoint from the strict-interior AP terms. Moreover,","Thus the correction spread is eventually smaller than the radix width. Residue gluing converts the lattice interval into an ordinary consecutive interval [ L M , U M ] [L_M,U_M] [ L M ​ , U M ​ ] satisfying","At this stage there is a genuine interval, but its multiplicative width is still only bounded by a constant. This is exactly where the earlier baseline problem remained.","The decisive idea was to exploit monomials that had not yet been used, on the same exact homogeneous level .","For each of linearly many indices s s s , fix a b b b -exponent just beyond every AP band. Among the remaining a , c a,c a , c -exponents, choose the last point of the geometric grid","below a target of size c v M c^{vM} c v M . Because consecutive grid points differ by the fixed factor c / a c/a c / a , the selected monomial lies in a controlled multiplicative window. After restoring the common factors, this produces at least M − O ( 1 ) M-O(1) M − O ( 1 ) distinct optional monomials z z z satisfying","Every optional term is therefore no larger than the already available interval width. Adding such a term optionally—either use it or do not—extends a consecutive interval without changing its lower endpoint. Since all optional terms remain on the same exact level and lie beyond the AP exponent bands, primitiveness and disjointness are preserved.","while the lower endpoint remains O ( B M ) O(B^M) O ( B M ) . Hence the ratio of the upper endpoint to the lower endpoint grows linearly with M M M . For every requested R > 1 R>1 R > 1 , and beyond every requested lower threshold, this constructs a primitively represented interval","This interior-shell amplification is what removes the finite-seed obstruction. The successful coordinate change was not merely “work on a homogeneous level,” but “place the main growth along an interior homogeneous ray, then use the unused transverse strip as optional mass.”","The residue-reduction argument was strengthened to a flexible finite-seed gate: there are constants N 0 N_0 N 0 ​ and C > 1 C>1 C > 1 such that any represented interval [ N , C N ] [N,CN] [ N , C N ] with N ≥ N 0 N\\ge N_0 N ≥ N 0 ​ implies d-completeness.","Applying the arbitrary-width construction with R = C R=C R = C proves d-completeness for ordered bases 1 a c b 1 1 a c b . Pairwise-coprime bases greater than one are distinct, so every triple has one of six strict orderings. Explicit permutations of the exponents show that permuting the bases leaves the smooth set unchanged, completing all cases.","The proof is formalized in Lean 4 with Mathlib. The final theorem is","where IntendedStatement quantifies over all pairwise-coprime natural bases greater than one and asserts an explicit eventual threshold for primitive representations.","The complete project builds successfully, and a source scan finds no proof placeholders. Lean’s axiom report for the final theorem is exactly","with no sorryAx . The webpage literally writes a , b , c ≥ 1 a,b,c\\ge1 a , b , c ≥ 1 ; that universal formulation is false at ( 1 , 1 , 1 ) (1,1,1) ( 1 , 1 , 1 ) . The project records this separately and proves the intended nondegenerate a , b , c > 1 a,b,c>1 a , b , c > 1 conjecture used in the source literature and independent formal-conjecture encoding.","The download contains everything needed to verify this solution independently: the original problem, the formal statement, the complete pinned Lean project, and the verifier script — plus step-by-step instructions for your agent. About 20 minutes, mostly downloading Mathlib.","↓ Download full solution raw：/downloads/verify/erdos-123/erdos-123-solution.zip","Let A ⊆ N A\\subseteq \\mathbb{N} A ⊆ N be such that ∣ A ∩ [ 1 , 2 x ] ∣ − ∣ A ∩ [ 1 , x ] ∣ → ∞ as x → ∞ \\lvert A\\cap [1,2x]\\rvert -\\lvert A\\cap [1,x]\\rvert \\to \\infty\\textrm{ as }x\\to \\infty ∣ A ∩ [ 1 , 2 x ]∣ − ∣ A ∩ [ 1 , x ]∣ → ∞ as x → ∞ and ∑ n ∈ A { θ n } = ∞ \\sum_{n\\in A} \\{ \\theta n\\}=\\infty n ∈ A ∑ ​ { θ n } = ∞ for every θ ∈ ( 0 , 1 ) \\theta\\in (0,1) θ ∈ ( 0 , 1 ) , where { x } \\{x\\} { x } is the distance of x x x from the nearest integer. Then every sufficiently large integer is the sum of distinct elements of A A A .","(Erdős Problem #254 — number theory — https://www.erdosproblems.com/254)","Erdős Problem #254 is true: if A ⊆ ℕ has dyadic shell counts tending to infinity and ∑_{n∈A} ‖θn‖ = ∞ for every real 0","Let A ⊆ ℕ . Assume that the number of elements of A in every dyadic shell (x,2x] tends to infinity, and that","for every 0 , where ‖x‖ is distance to the nearest integer. Erdős asked whether these two hypotheses force every sufficiently large integer to be a sum of distinct elements of A .","The hypotheses control two very different phenomena:","Neither condition alone is close to sufficient. The real difficulty is to assign disjoint elements of A to several roles—two piecewise-Bohr classes, a phase-correction class, and a final syndetic class—without destroying the phase hypothesis or reusing a summand.","Several tempting shortcuts are false.","The key was therefore to solve the allocation problem globally and replace the missing ergodic machinery by a finite-cyclic spectral proof that could be kernel-checked from first principles.","The decisive structural observation is that dyadic abundance makes the set of phases with finite total mass countable .","two sufficiently close phases cannot both satisfy that bound. Indeed, if their difference is δ , look at a dyadic shell at scale about 1/(8δ) . Every element of that shell contributes a controlled positive amount to the difference phase, and the growing shell cardinality contradicts the assumed bound. Hence every bounded phase sublevel is finite, and the union of those sublevels is countable.","This converts an uncountable allocation problem into a countable diagonalization. We split off a shell-abundant seed, enumerate only its countably many convergent phases, and balance reserves against those phases. The resulting reserve has syndetic distinct subset sums, while its actual complement still has divergent phase mass for every nonzero phase. Splitting the reserve by rank produces three pairwise-disjoint syndetic finite-sum classes and a disjoint universally phase-divergent correction class.","That resolves the support-allocation obstruction completely.","The remaining input was the Bergelson–Furstenberg–Weiss theorem: the sum of two syndetic subsets of ℕ contains a piecewise-Bohr set.","Instead of formalizing an abstract Kronecker factor, we built the spectral argument from finite cyclic groups.","A syndetic set has a uniformly positive number of points in long finite blocks. Given dense blocks from two syndetic sets, finite cyclic averaging finds a large fiber on which all pairs have the same exact sum. A dense subblock of that fiber has the property that each positive internal difference, after one common translation, belongs to the original sumset.","For a signal Φ : ZMod N → ℂ , we proved Parseval’s identity for Mathlib’s unnormalized DFT:"],"articleImages":[],"mediaStatus":"none","articleBodyZh":[],"translationStatus":"","bodyOrigin":"source-page","editorial":{"summary":"Aioga 编辑摘要：Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。 Aioga 将其归入「产品更新」方向，重点关注它对真实使用和行业竞争的影响。","background":"背景分析：产品与工具类动态的价值取决于它是否解决明确场景、能否进入工作流，以及交付、价格和数据安全是否可接受。","viewpoint":"Aioga 判断：这条动态更适合作为行业观察信号，当前信息足以建立线索，但不足以推导长期结论。","implications":"影响分析：对相关团队而言，短期应先核对来源、可用范围和实际成本，再判断是否值得接入或跟进。","nextStep":"后续观察：继续观察产品是否开放使用、用户反馈、定价、集成能力和后续版本更新。","evidenceRefs":["title","summary","articleBody"],"confidence":"medium","status":"published","aiGenerated":false,"autoApproved":true,"generatedBy":"rule-safe-fallback","generatedAt":"2026-07-23T08:10:16.922Z","sourceHash":"ab50a3daafdb2313","validation":{"passed":true,"mode":"rule-safe-fallback","checks":["schema","length","source-attribution","no-html"]}},"tags":["产品更新","Hacker News 热门（buzzing.cc 中文翻译）"],"translations":{"zh-CN":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga AI资讯","description":"Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","url":"https://www.aioga.com/news/cmrlpa4rs00eybih5qt1ohw0o/"},"en":{"title":"利用20个并行运行的Codex账户解决20个埃尔德什问题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under Products. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"Products","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"利用20个并行运行的Codex账户解决20个埃尔德什问题 - Aioga AI News","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under Products. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 ","url":"https://www.aioga.com/en/news/cmrlpa4rs00eybih5qt1ohw0o/"},"ja":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aiogaは「製品更新」の動きとして、Hacker News 热门（buzzing.cc 中文翻译） からの更新を追跡しています。Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"製品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga AIニュース","description":"Aiogaは「製品更新」の動きとして、Hacker News 热门（buzzing.cc 中文翻译） からの更新を追跡しています。Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、L","url":"https://www.aioga.com/ja/news/cmrlpa4rs00eybih5qt1ohw0o/"},"ko":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga는 Hacker News 热门（buzzing.cc 中文翻译）의 업데이트를 제품 업데이트 흐름으로 추적합니다. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"제품 업데이트","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga AI 뉴스","description":"Aioga는 Hacker News 热门（buzzing.cc 中文翻译）의 업데이트를 제품 업데이트 흐름으로 추적합니다. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、","url":"https://www.aioga.com/ko/news/cmrlpa4rs00eybih5qt1ohw0o/"},"es":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga sigue esta actualización de Hacker News 热门（buzzing.cc 中文翻译） dentro de Productos. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"Productos","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga Noticias de IA","description":"Aioga sigue esta actualización de Hacker News 热门（buzzing.cc 中文翻译） dentro de Productos. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学","url":"https://www.aioga.com/es/news/cmrlpa4rs00eybih5qt1ohw0o/"},"fr":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga suit cette mise à jour de Hacker News 热门（buzzing.cc 中文翻译） dans la catégorie Produits. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"Produits","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga Actualités IA","description":"Aioga suit cette mise à jour de Hacker News 热门（buzzing.cc 中文翻译） dans la catégorie Produits. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处","url":"https://www.aioga.com/fr/news/cmrlpa4rs00eybih5qt1ohw0o/"},"de":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga KI-News","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/de/news/cmrlpa4rs00eybih5qt1ohw0o/"},"pt-BR":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga Notícias de IA","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/pt-BR/news/cmrlpa4rs00eybih5qt1ohw0o/"},"ru":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga Новости ИИ","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/ru/news/cmrlpa4rs00eybih5qt1ohw0o/"},"ar":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga أخبار الذكاء الاصطناعي","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/ar/news/cmrlpa4rs00eybih5qt1ohw0o/"},"hi":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga AI समाचार","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/hi/news/cmrlpa4rs00eybih5qt1ohw0o/"},"it":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga Notizie IA","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/it/news/cmrlpa4rs00eybih5qt1ohw0o/"},"nl":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga AI-nieuws","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/nl/news/cmrlpa4rs00eybih5qt1ohw0o/"},"tr":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga AI Haberleri","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/tr/news/cmrlpa4rs00eybih5qt1ohw0o/"},"vi":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Tin tức AI Aioga","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/vi/news/cmrlpa4rs00eybih5qt1ohw0o/"},"id":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Berita AI Aioga","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/id/news/cmrlpa4rs00eybih5qt1ohw0o/"},"th":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - ข่าว AI Aioga","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/th/news/cmrlpa4rs00eybih5qt1ohw0o/"},"pl":{"title":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题","summary":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100 GPU 集群、Lean 4 语料库及 CaDiCaL、Z3 等求解器，目前已提出 27 个解决方案。","category":"产品更新","source":"Hacker News 热门（buzzing.cc 中文翻译）","pageTitle":"Star Fleet：用20个并行GPT-5.6智能体解决埃尔德什难题 - Aioga Wiadomości AI","description":"Aioga tracks this update from Hacker News 热门（buzzing.cc 中文翻译） under 产品更新. Star Fleet 是一个基于 Lean 4 的 AI 系统，通过 Mac 桌面应用并行控制 20 个独立 GPT-5.6 实例，每个实例配备 60 vCPU 服务器，分别处理一个数学问题。系统集成了 H100","url":"https://www.aioga.com/pl/news/cmrlpa4rs00eybih5qt1ohw0o/"}}}}